3x^2+10.25x-7=0

Solution for 3x^2+10.25x-7=0 equation:

3x^2+10.25x-7=0

a = 3; b = 10.25; c = -7;
Δ = b2-4ac
Δ = 10.252-4·3·(-7)
Δ = 189.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10.25)-\sqrt{189.0625}}{2*3}=\frac{-10.25-\sqrt{189.0625}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10.25)+\sqrt{189.0625}}{2*3}=\frac{-10.25+\sqrt{189.0625}}{6}
$